(2x-1/2)^2=9/4

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Solution for (2x-1/2)^2=9/4 equation:


x in (-oo:+oo)

(2*x-(1/2))^2 = 9/4 // - 9/4

(2*x-(1/2))^2-(9/4) = 0

(2*x-1/2)^2-9/4 = 0

(4*(2*x-1/2)^2)/4-9/4 = 0

4*(2*x-1/2)^2-9 = 0

16*x^2-8*x-8 = 0

16*x^2-8*x-8 = 0

8*(2*x^2-x-1) = 0

2*x^2-x-1 = 0

DELTA = (-1)^2-(-1*2*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)+1)/(2*2) or x = (1-9^(1/2))/(2*2)

x = 1 or x = -1/2

8*(x+1/2)*(x-1) = 0

(8*(x+1/2)*(x-1))/4 = 0

(8*(x+1/2)*(x-1))/4 = 0 // * 4

8*(x+1/2)*(x-1) = 0

( 8 )

8 = 0

x belongs to the empty set

( x+1/2 )

x+1/2 = 0 // - 1/2

x = -1/2

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -1/2, 1 }

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